Success Bureau
Smart Learning
India's Premier Institute for NRA CET
Learn From The Industry Experts
TEST OF QUANTITATIVE APTITUDE
The Quantitative Aptitude Section of Success Bureau Study Material covers the complete syllabus and includes Often Asked Questions
( OAQs) in the Competitive Examinations .
Hence, you are advised to properly cram the contents . You should not waste time in learning out dated books .
Below is given a small Sample of the Study Material provided to the students .
PERCENTAGE
Percentage Rule - 1
A Fraction, whose Denominator is 100, is called the Percentage or Rate Percentage and the Numerator of the Fraction is Denoted by % .
For example, 25% means 25 out of 100 This can be expressed as 25 / 100 = 1/ 4
Similarly, 100% means 100 / 100 = 1.
Percentage Rule - 2
(A) Multiply by 100 if you want to Show a Certain Number in % .
(B) Divide by 100 if you want to Remove % Sign from a Certain Number .
Examples : Q.1 2 / 10 as a rate per cent is ?
Solution : 2 / 10 x 100 = 20% .
Q.2 3.793 as a rate per cent is ?
Solution : 3.793 x 100 = 379.3 %
Q.3 20% = ?
Solution : 20 / 100 = 1 / 5
Q.4 3.768 % = ?
Solution : 3.768 / 100 = 0.03768
Percentage Rule - 3
In Competitive Examinations, the Questions Based on the Following Relationship of A, B and C, are Often Asked :
A % of B = C |
In such problems, You are required to find out the Value of Any of the Three ( i.e. A, B or C ) on the basis of the Given Values of any Two .
These Problems can be Easily Solved in the following way :
A = C x 100 / B |
B = C x 100 / A |
C = A x B / 100 |
Examples : Q.1 Find out the value of X if X % of 200 is equal to 50 .
Solution : X = 50 x 100 / 200 = 25
Q.2 20 is what % of 80 or X % of 80 is 20 ?
Solution : X = 20 x 100 / 80 = 25 %
Q.3 40% of 600 is equal to what ?
Solution : Suppose, 40% of 600 = X . Hence , X = 40 x 600 / 100 = 240
Memories the following relationships given in the Chart below. It will help you in solving the percentage questions quickly :
CHART-1
5 % = 1/20 | 55 % = 11/20 |
10 % = 1/10 | 65 % = 13/20 |
15 % = 3/20 | 85 % = 17/20 |
20 % = 1/5 | 75 % = 3/4 |
25 % = 1/4 | 50 % = 1/2 |
35 % = 7/20 | 100 % = 1 |
40 % = 2/5 | 45 % = 9/20 |
From the above chart we can see that for obtaining 5% of a certain number, we have to divide the number by 20 and so on .
100 % = 1 | 200 % = two times of anything |
Similarly, | 25 % = 1 / 4 of anything |
20 % = 1 / 5 of anything | 10 % = 1 / 10 of anything |
100 % of 10 will be 10 x 1 = 10 | 200 % of 10 will be 10 x 2 = 20 |
400 % of 10 will be 10 x 4 = 40 | 50 % of 10 will be 10 x 1 / 2 = 5 |
25 % of 10 will be 10 x 1 / 4 = 25 | 10 % of 10 will be 10 x 1 / 10 = 1 |
Examples :
Q.1 5% of 80 = ?
Solution : 80 x 1/20 = 4
Q.2 20% of 400 = ?
Solution : 400 x 1/5 = 80
Q.3 35% of 900 = ?
Solution : 900 x 7/20 = 315
Q.4 12.5% of 200 = ?
Solution : 200 X 1/8 = 25
Q.5. Two numbers are respectively 20% and 40% more than a third number. What is the ratio of the two numbers ?
Solution : Suppose the third number is 100 .
Hence, the Ist and IInd numbers would naturally be 120 and 140 respectively. Ratio = 120 : 140 = 6 : 7.
Q.6. A Regiment lost in an engagement 25% of its men and still had 300 men left . What was the original number of men in the regiment ?
Solution : 75% ( or 3/4th ) of original men = 300 . Hence , Original men = 300 x 4/3 = 400
Q.7. The number of seats for admission for a vocational course is increased by 15% every year. If the number of students in 2017 is 800, what is the expected number of students in 2019 ?
Solution : The no. of seats increases by 15% ever year. So, 800 x 115 / 100 x 115 / 100 = 1058
Q.8. 30% of A’ s salary is equal to the 20% of 3/5th of B’ s salary. If B’s salary is Rs. 24,000/- , what is A’s salary ?
Solution : Suppose A’s salary is Rs. X.
Then, 3X / 10 = 1 / 5 x 3 / 5 x 24000/- ( 30% = 3/10 , 20% = 1/5 ) Or X = Rs. 9600/-
Q.9. In a library, 40% of the total number of books are in English, 80% of the rest in Hindi and the balance 300 books are in other languages. What is the total number of books in the library ?
Solution : Suppose total number of books = X
Hence, 40% of X + 80% of ( X – 40% ) + 300 = X Or 2X / 5 + 4 / 5 ( X – 2X / 5 ) + 300 = X Or X = 2500
Q.10. After deducting 20% from a certain sum and then 25% from the remainder, there are Rs.1200/- left . Find the original sum .
Solution : Suppose the original sum was Rs. X. After deducting 20%, 80% of X is left .
Then after deducting 25% of the remainder 75% of it would be left which is equal to Rs. 1200/-
The whole process can be shown like this : 4X / 5 x 3 / 4 = 1200 ( 80% = 4 / 5 , 75% = 3 / 4
Or X = Rs. 2000
Special Note
The Quantitative Aptitude Section of Success Bureau Study Material covers complete syllabus and includes Often Asked Questions ( OAQs ) in the Competitive Examinations .
Hence, you are advised to properly cram the contents . You should not waste time in learning out dated books .
Above is given a small sample of the Study Material provided to the students .
English
Gujarati
Hindi
Kannada
Malayalam
Marathi
Punjabi
Sindhi
Sinhala
Tamil
Telugu
Urdu